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The problem is, that

  (equal 1 1) -> t
  (equal '(1 2) '(1 2)) -> t

  (eq 1 1) -> t
  (eq '(1 2) '(1 2)) -> nil
because eq tests for the same symbol, while equal test for the same list. Member uses eq, not equal.


If we are talking Common Lisp, the default test is actually EQL. ((eq 1 1) is not necessarily T).


Ah, I see. Thanks.




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