It's not b64 encoding the final byte of the hash, not dropping a b64 character. | Hacker News

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		daeken on June 14, 2011 \| parent \| context \| favorite \| on: A possible flaw in open-source bcrypt implementati... It's not b64 encoding the final byte of the hash, not dropping a b64 character.

stavros on June 14, 2011 [–]

Ah, I see. You are correct, then. Also, that would make it 64 times, if I were right, it seems.

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